Print(letter[0], letter[1])

Python
1

letters = [“a”, “b”, “c”]
items = [0, “a”]
index, letter = items
for letter in enumerate(letters):
print(letter[0], letter[1])

Why letter[1] refers to the letters in the list ?

2

Hey @Lt.Smith,

Because you used “letters” in the for loop which points to [“a”, “b”, “c”].

BTW “letter”(line 3) is declared as “a” initially but over written in the for loop(line 4). Is that intentional?

1 Like
3

I just wrote the code like Mosh, just copy-paste

4

Which lecture was it?

5

Looping over Lists from the Data Structures chapter.

But the code that I posted is not the finished code, I just didn’t understand why letter[1] was referring to the letters.

6

No worry’s, just curious.

Was I able to answer your question?

1 Like
7

Yeah, you did. Thank you!

8

Anytime.

If you run into anything else or just looking for advice, the forums are here for you.

9

Thank you!Good to know ! :smiley:

10

Hi again!

Do you know why we need to wrote return item[1] in the bellow code:

items = [(“Product1”, 8),
(“Product2”, 15),
(“Product3”, 6)
]

def sort_item(item):
return item[1]

items.sort(key=sort_item)
print(items)

Sorting lists lesson

11

If you recall from lists that every item has an index starting with 0. item[1] simply means get the second value. i.e (“Product1”, 8) gets the number 8.

Its not clear but sort has a for loop looping through the items list. gets a tuple(e.x (“Product1”, 8)). Then it passes the tuple into your function"sort_item" and returns the second value. once it gets the second values it sorts it based on the number.

1 Like
12

Hi again!

Anther question if you don’t mind:)
What is the difference between a signed integer and an unsigned one?

13

Here is a stack post that explains it well.

1 Like
14

Thank you! That kind of examples really helps. As simple as possible, otherwise my brains boils :frowning: