Hi there,
in this exercise of operator, ‘c’ is not supposed to be blue since a = b?
Hi.
The value should be red.
You instantiate a and b
then c from a
So c has the value of a
Then you change the value of a which is independent from c.
The way you are thinking of it is called “by reference” but it is “by value”.
Chronologically it goes something like this:
| a | b | c | Instruction |
|---|---|---|---|
| ‘red’ | let a = 'red' |
||
| ‘red’ | ‘blue’ | let b = 'blue' |
|
| ‘red’ | ‘blue’ | ‘red’ | let c = a |
| ‘blue’ | ‘blue’ | ‘red’ | a = b |
Regards.
1 Like
That is a heck of an explanation 
.
So when I initially assign the variable c to the value of a, c won’t be affected when I later change the value of a for b?
Yes.
You can read those articles:
Primitive and Reference value in JavaScript @G4G
Pass by Value and Pass by Reference in Javascript @G4G
Regards.